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-0.5x^2+2.5x+1=1.5x
We move all terms to the left:
-0.5x^2+2.5x+1-(1.5x)=0
We add all the numbers together, and all the variables
-0.5x^2+2.5x-(+1.5x)+1=0
We get rid of parentheses
-0.5x^2+2.5x-1.5x+1=0
We add all the numbers together, and all the variables
-0.5x^2+x+1=0
a = -0.5; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·(-0.5)·1
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3}}{2*-0.5}=\frac{-1-\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3}}{2*-0.5}=\frac{-1+\sqrt{3}}{-1} $
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